CH3OCH3 (Dimethyl ether) is a POLAR molecule.
But why?
And how can you say that CH3OCH3 is a polar molecule?
Want to know the reason?
Let’s dive into it!
CH3OCH3 is a POLAR molecule because the Oxygen (O) present in the molecule is more electronegative, which causes the partial positive (ẟ+) and partial negative (ẟ-) charge to appear on the molecule. These ẟ+ and ẟ- charges are responsible to make the entire CH3OCH3 molecule polar.
Let me explain this in detail with the help of CH3OCH3 lewis structure and its 3D geometry.
Why is CH3OCH3 a Polar molecule? (Explained in 2 Steps)
CH3OCH3 is a polar molecule because it has poles of partial positive charge (ẟ+) and partial negative charge (ẟ-) on it.
Let me explain this to you in 2 steps!
Step #1: Draw the lewis structure
Here is a skeleton of CH3OCH3 lewis structure and it contains C-H bonds and C-O bonds.
(Note: If you want to know the steps of drawing the CH3OCH3 lewis dot structure, then visit this article: CH3OCH3 lewis structure).
So from the above diagram we have come to know that the CH3OCH3 molecule has C-H bonds and C-O bonds.
Now in the next step we have to check whether these C-H bonds and C-O bonds are polar or nonpolar.
And we also have to check the molecular geometry of CH3OCH3.
Step #2: Check the bond polarity and molecular geometry
The chemical bonds can be either nonpolar, polar or ionic depending on the difference of the electronegativity values (ΔEN) between the two atoms.
Have a look at the above image.
- If the electronegativity difference (ΔEN) is less than 0.4, then the bond is nonpolar covalent bond.
- If the electronegativity difference (ΔEN) is between 0.4 to 1.7, then the bond is polar covalent bond.
- If the electronegativity difference (ΔEN) is greater than 1.7, then the bond is an ionic bond. [1] [2] [3] [4]
Now let’s come to the example of CH3OCH3 molecule. It has C-H bonds and C-O bonds.
You can see the electronegativity values of Carbon (C), Hydrogen (H) and Oxygen (O) atoms from the periodic table given below.
From the above image;
- Electronegativity of Carbon (C) = 2.55 [5]
- Electronegativity of Hydrogen (H) = 2.2 [6]
- Electronegativity of Oxygen (O) = 3.44 [7]
Now let’s see the polarity of each bond.
For C-H bond;
The electronegativity difference (ΔEN) = 2.55 – 2.2 = 0.35
This value is less than 0.4, which indicates that the bond between Carbon (C) and Hydrogen (H) is nonpolar.
Hence, each C-H bond is a nonpolar covalent bond.
For C-O bond;
The electronegativity difference (ΔEN) = 3.44 – 2.55 = 0.89
This value lies between 0.4 to 1.7, which indicates that the bond between Carbon (C) and Oxygen (O) is polar.
Hence, each C-O bond is a polar covalent bond.
You can see in the above image that because of higher electronegativity of Oxygen atom, the partial positive charge (ẟ+) appears on the Carbon atom (C) as well as Hydrogen atoms (H) and partial negative charge (ẟ-) appears on the Oxygen atom (O).
From this, you can easily get the idea that the CH3OCH3 molecule is a polar molecule.
But let’s also see its 3D molecular geometry for better understanding.
Have a look at this 3D structure of CH3OCH3. The more electronegative oxygen atom (O) has a tendency to pull the shared electron pair towards itself, which results in partial positive charge on carbon atom (C) & hydrogen atom (H) and partial negative charge on oxygen atom (O).
Because of this, there are positive and negative poles of charges on the overall molecule of CH3OCH3.
Hence, the CH3OCH3 molecule is a polar molecule.
I hope you have understood the reason behind the polar nature of CH3OCH3 molecule.
See the polarity of other molecules to make your concepts clear:
Is BrCl3 Polar or Nonpolar?
Is HI Polar or Nonpolar?
Is SeO2 Polar or Nonpolar?
Is OH- Polar or Nonpolar?
Is SeF6 Polar or Nonpolar?
Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. With a desire to make learning accessible for everyone, he founded Knords Learning, an online learning platform that provides students with easily understandable explanations.
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