Molar mass of PbBr2 is 367.008 g/mol.
Well, now you have come to know the molar mass of PbBr2.
But how can you get this value?
Let me show you the calculation to get the molar mass of PbBr2.
You can also refer to this one minute video which will show you the simple steps to calculate the molar mass of any compounds.
PbBr2 Molar Mass Calculation
If you have a periodic table with you, then you can easily calculate the molar mass of PbBr2.
Because the molar mass of any molecule (or compound) can be calculated by simply adding the molar masses of individual atoms.
Now here we have to find the molar mass of PbBr2.
So for that, have a look at the periodic table given below.
You can see the molar mass value of all the atoms from this periodic table.
Now in PbBr2, there is 1 Lead atom and 2 Bromine atoms.
So let’s look at the molar mass of Lead and Bromine from the above periodic table.
You can see that;
The molar mass of Lead is 207.2 g/mol. 
The molar mass of Bromine is 79.904 g/mol. 
Now, to calculate the molar mass of PbBr2, you just have to add the molar mass of all the individual atoms that are present in PbBr2.
You can see that in PbBr2, there is 1 Lead atom and 2 Bromine atoms.
So, Molar mass of PbBr2 = Molar mass of 1 Lead (Pb) atom + Molar mass of 2 Bromine (Br) atoms.
= 207.2 + (79.904) 2
= 207.2 + 159.808
= 367.008 g/mol
Hence the Molar mass of PbBr2 is 367.008 g/mol.
I hope you have understood the short and simple calculation for finding the molar mass of PbBr2.
- In some books, you may see the unit of molar mass as grams/mole or g/mole. But all these units (i.e g/mol, grams/mole and g/mole) are the same.
- Always follow the calculation order to avoid any mistakes in calculation. First solve the brackets, then multiplications and at last do the final addition.
- And don’t forget to put the unit g/mol to your final calculated molar mass.
Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. With a desire to make learning accessible for everyone, he founded Knords Learning, an online learning platform that provides students with easily understandable explanations.
Read more about our Editorial process.