AgI (Silver iodide) Molar Mass (With Calculations)

Molar mass of AgI (Silver iodide) is 234.77 g/mol.

Well, now you have come to know the molar mass of AgI.

But how can you get this value?

Let me show you the calculation to get the molar mass of AgI (Silver iodide).

You can also refer to this one minute video which will show you the simple steps to calculate the molar mass of any compounds.

AgI (Silver iodide) Molar Mass Calculation

If you have a periodic table with you, then you can easily calculate the molar mass of AgI (Silver iodide).

Because the molar mass of any molecule (or compound) can be calculated by simply adding the molar masses of individual atoms.

Now here we have to find the molar mass of AgI (Silver iodide).

So for that, have a look at the periodic table given below.

You can see the molar mass value of all the atoms from this periodic table.

Now in AgI, there is 1 Silver atom and 1 Iodine atom.

So let’s look at the molar mass of Silver and Iodine from the above periodic table.

You can see that;

The molar mass of Silver is 107.87 g/mol. ^[1]

The molar mass of Iodine is 126.90 g/mol. ^[2]

Now, to calculate the molar mass of AgI, you just have to add the molar mass of all the individual atoms that are present in AgI.

You can see that in AgI, there is 1 Silver atom and 1 Iodine atom.

So, Molar mass of AgI = Molar mass of 1 Silver (Ag) atom + Molar mass of 1 Iodine (I) atom.
= 107.87 + 126.90
= 234.77 g/mol

Hence the Molar mass of AgI is 234.77 g/mol.

I hope you have understood the short and simple calculation for finding the molar mass of AgI.

Remember

• In some books, you may see the unit of molar mass as grams/mole or g/mole. But all these units (i.e g/mol, grams/mole and g/mole) are the same. 
• Always follow the calculation order to avoid any mistakes in calculation. First solve the brackets, then multiplications and at last do the final addition.
• And don’t forget to put the unit g/mol to your final calculated molar mass.

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