Lewis Structure of COBr2 (With 6 Simple Steps to Draw!)

Lewis Structure of COBr2

I’m super excited to teach you the lewis structure of COBr2 in just 6 simple steps.

Infact, I’ve also given the step-by-step images for drawing the lewis dot structure of COBr2 molecule.

So, if you are ready to go with these 6 simple steps, then let’s dive right into it!

Lewis structure of COBr2 contains a double bond between the Carbon (C) & Oxygen (O) atom and two single bonds between Carbon (C) & Bromine (Br) atoms. The Carbon atom (C) is at the center and it is surrounded by two Bromine (Br) and one Oxygen atom (O).

Let’s draw and understand this lewis dot structure step by step.

(Note: Take a pen and paper with you and try to draw this lewis structure along with me. I am sure you will definitely learn how to draw lewis structure of COBr2).

6 Steps to Draw the Lewis Structure of COBr2

Step #1: Calculate the total number of valence electrons

Here, the given molecule is COBr2. In order to draw the lewis structure of COBr2, first of all you have to find the total number of valence electrons present in the COBr2 molecule.
(Valence electrons are the number of electrons present in the outermost shell of an atom).

So, let’s calculate this first.

Calculation of valence electrons in COBr2

  • For Carbon:

Carbon is a group 14 element on the periodic table.

Hence, the valence electrons present in carbon is 4 (see below image).

  • For Oxygen:

Oxygen is a group 16 element on the periodic table.

Hence, the valence electron present in oxygen is 6 (see below image).

  • For Bromine:

Bromine is a group 17 element on the periodic table.

Hence, the valence electrons present in bromine is 7 (see below image).

Hence in a COBr2 molecule, 

Valence electrons given by Carbon (C) atom = 4
Valence electrons given by Oxygen (O) atom = 6
Valence electrons given by each Bromine (Br) atom = 7
So, total number of Valence electrons in COBr2 molecule = 4 + 6 + 7(2) = 24

Step #2: Select the center atom

While selecting the center atom, always put the least electronegative atom at the center.

(Remember: Fluorine is the most electronegative element on the periodic table and the electronegativity decreases as we move right to left in the periodic table as well as top to bottom in the periodic table). [1]

Here in the COBr2 molecule, if we compare the carbon atom (C), oxygen atom (O) and bromine atom (Br), then the carbon is less electronegative.

So, carbon should be placed in the center and the oxygen atom as well as bromine atom will surround it.

step 1

Step #3: Put two electrons between the atoms to represent a chemical bond

Now in the above sketch of COBr2 molecule, put the two electrons (i.e electron pair) between the carbon-oxygen atoms and carbon-bromine atoms to represent a chemical bond between them.

step 2

These pairs of electrons present between the Carbon & Oxygen atoms as well as between the Carbon & Bromine atoms form a chemical bond, which bonds these atoms with each other in a COBr2 molecule.

Step #4: Complete the octet (or duplet) on outside atoms. If the valence electrons are left, then put the valence electrons pair on the central atom

Don’t worry, I’ll explain!

In the Lewis structure of COBr2, the outer atoms are bromine atoms and oxygen atom.

You also have to see whether the oxygen atom as well as bromine atoms are forming an octet or not! (because oxygen and bromine both require 8 electrons to have a complete outer shell).

step 3

You can see in the above image that both the bromine atoms as well as one oxygen atom forms an octet.

Also, all the 24 valence electrons of COBr2 molecule (as calculated in step #1) are used in the above structure. So there are no remaining electron pairs.

Hence there is no change in the above sketch of COBr2.

Let’s move to the next step.

Step #5: Check whether the central atom has octet or not. If it does not have an octet, then move the electron pair from the outer atom to form a double bond or triple bond

In this step, we have to check whether the central atom (i.e carbon) has an octet or not. 

In simple words, we have to check whether the central Carbon (C) atom has 8 electrons or not.

step 4

As you can see from the above image, the central atom (i.e carbon) has only 6 electrons. So it does not fulfill the octet rule.

Now, in order to fulfill the octet of a carbon atom, we have to move the electron pair from the outer atom (i.e oxygen atom) to form a double bond.

step 5

Now you can see from the above image that the central atom (i.e carbon), is having 8 electrons. So it fulfills the octet rule.

Step #6: Final step – Check the stability of lewis structure by calculating the formal charge on each atom

Now, you have come to the final step and here you have to check the formal charge on carbon atom (C), oxygen (O) atom as well as bromine atoms (Br).

For that, you need to remember the formula of formal charge;

Formal charge = Valence electrons – Nonbonding electrons – (Bonding electrons)/2

step 6
  • For Carbon:
    Valence electrons = 4 (as it is in group 14)
    Nonbonding electrons = 0
    Bonding electrons = 8
  • For Oxygen:
    Valence electron = 6 (as it is in group 16)
    Nonbonding electrons = 4
    Bonding electrons = 4
  • For Bromine:
    Valence electron = 7 (as it is in group 17)
    Nonbonding electrons = 6
    Bonding electrons = 2
Formal charge=Valence electronsNonbonding electrons(Bonding electrons)/2

So you can see above that the formal charges on carbon, oxygen as well as bromine are “zero”.

Hence, there will not be any change in the above structure and the above lewis structure of COBr2 is the final stable structure only.

Each electron pair (:) in the lewis dot structure of COBr2 represents the single bond ( | ). So the above lewis dot structure of COBr2 can also be represented as shown below.

cobr2 lewis structure

(Note: In step 5, if we had moved the electron pair from the bromine atom, then there will be +1 and -1 charges on bromine and oxygen respectively. But here we move the electron pair from the oxygen atom, which gives the more stable structure (having “zero” charges on all the atoms.))

Related lewis structures for your practice:
Lewis Structure of GeF4
Lewis Structure of Cl2O2
Lewis Structure of XeI2
Lewis Structure of PF2Cl3
Lewis Structure of IBr4- 

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Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. With a desire to make learning accessible for everyone, he founded Knords Learning, an online learning platform that provides students with easily understandable explanations.

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