# BaCl2 · 2H2O Molar Mass (With Calculation)

Molar mass of BaCl2 · 2H2O is 244.26 g/mol.

Well, now you have come to know the molar mass of BaCl2 · 2H2O.

But how can you get this value?

Let me show you the calculation to get the molar mass of BaCl2 · 2H2O.

If you are a visual learner like me, then here is a short one minute video for you.

## BaCl2 · 2H2O Molar Mass Calculation

If you have a periodic table with you, then you can easily calculate the molar mass of BaCl2 · 2H2O.

Because the molar mass of any molecule (or compound) can be calculated by simply adding the molar masses of individual atoms.

Now here we have to find the molar mass of BaCl2 · 2H2O.

So for that, have a look at the periodic table given below.

You can see the molar mass value of all the atoms from this periodic table.

Now in BaCl2 · 2H2O, there is Barium atom, Chlorine atoms, Hydrogen atoms and Oxygen atoms.

So let’s look at the molar mass of Barium, Chlorine, Hydrogen and Oxygen from the above periodic table.

You can see that;

The molar mass of Barium is 137.33 g/mol. [1]

The molar mass of Chlorine is 35.45 g/mol. [2]

The molar mass of Hydrogen is 1.008 g/mol. [3]

The molar mass of Oxygen is 15.999 g/mol. [4]

Now, to calculate the molar mass of BaCl2 · 2H2O, you just have to add the molar mass of all the individual atoms that are present in BaCl2 · 2H2O.

So, Molar mass of BaCl2 · 2H2O = {Molar mass of Barium atom + (Molar mass of Chlorine atom × 2)} + [2 × {(Molar mass of Hydrogen × 2) + Molar mass of Oxygen}]
= {137.33 + (35.45) 2} + [2 × {(1.008 × 2) + 15.999}]
= {137.33 + 70.9} + [2 × {(2.016) + 15.999}]
= {208.23} + [2 × {18.015}]
= {208.23} + [36.03]
= 244.26 g/mol

Hence the Molar mass of BaCl2 · 2H2O is 244.26 g/mol.

I hope you have understood the short and simple calculation for finding the molar mass of BaCl2 · 2H2O.

Remember

• In some books, you may see the unit of molar mass as grams/mole or g/mole. But all these units (i.e g/mol, grams/mole and g/mole) are the same.
• Always follow the calculation order to avoid any mistakes in calculation. First solve the brackets, then multiplications and at last do the final addition.
• And don’t forget to put the unit g/mol to your final calculated molar mass.
Author
##### Jay Rana

Jay is an educator and has helped more than 100,000 students in their studies by providing simple and easy explanations on different science-related topics. With a desire to make learning accessible for everyone, he founded Knords Learning, an online learning platform that provides students with easily understandable explanations.