# Lewis Structure of CSe2 (With 6 Simple Steps to Draw!)

I’m super excited to teach you the lewis structure of CSe2 in just 6 simple steps.

Infact, I’ve also given the step-by-step images for drawing the lewis dot structure of CSe2 molecule.

So, if you are ready to go with these 6 simple steps, then let’s dive right into it!

Lewis structure of CSe2 contains two double bonds between the Carbon (C) atom and each Selenium (Se) atom. The Carbon atom (C) is at the center and it is surrounded by 2 Selenium atoms (Se). The Carbon atom does not have a lone pair while both the Selenium atoms have 2 lone pairs.

Let’s draw and understand this lewis dot structure step by step.

(Note: Take a pen and paper with you and try to draw this lewis structure along with me. I am sure you will definitely learn how to draw lewis structure of CSe2).

## 6 Steps to Draw the Lewis Structure of CSe2

### Step #1: Calculate the total number of valence electrons

Here, the given molecule is CSe2. In order to draw the lewis structure of CSe2, first of all you have to find the total number of valence electrons present in the CSe2 molecule.
(Valence electrons are the number of electrons present in the outermost shell of an atom).

So, let’s calculate this first.

Calculation of valence electrons in CSe2

• For Carbon:

Carbon is a group 14 element on the periodic table.

Hence, the valence electrons present in carbon is 4 (see below image).

• For Selenium:

Selenium is a group 16 element on the periodic table.

Hence, the valence electrons present in selenium is 6 (see below image).

Hence in a CSe2 molecule,

Valence electrons given by Carbon (C) atom = 4
Valence electrons given by each Selenium (Se) atom = 6
So, total number of Valence electrons in CSe2 molecule = 4 + 6(2) = 16

### Step #2: Select the center atom

While selecting the atom, always put the least electronegative atom at the center.

(Remember: Fluorine is the most electronegative element on the periodic table and the electronegativity decreases as we move right to left in the periodic table as well as top to bottom in the periodic table).

Here in the CSe2 molecule, if we compare the carbon atom (C) and selenium atom (Se), then the carbon is less electronegative than selenium.

So, carbon should be placed in the center and the remaining 2 selenium atoms will surround it.

### Step #3: Put two electrons between the atoms to represent a chemical bond

Now in the above sketch of CSe2 molecule, put the two electrons (i.e electron pair) between each carbon atom and selenium atom to represent a chemical bond between them.

These pairs of electrons present between the Carbon (C) and Selenium (Se) atoms form a chemical bond, which bonds the carbon and selenium atoms with each other in a CSe2 molecule.

### Step #4: Complete the octet (or duplet) on outside atoms. If the valence electrons are left, then put the valence electrons pair on the central atom

Don’t worry, I’ll explain!

In the Lewis structure of CSe2, the outer atoms are selenium atoms.

So now, you have to complete the octet on these selenium atoms (because selenium requires 8 electrons to have a complete outer shell).

Now, you can see in the above image that all the selenium atoms form an octet.

Also, all the 16 valence electrons of CSe2 molecule (as calculated in step #1) are used in the above structure. So there are no remaining electron pairs.

Hence there is no change in the above sketch of CSe2.

Let’s move to the next step.

### Step #5: Check whether the central atom has octet or not. If it does not have an octet, then move the electron pair from the outer atom to form a double bond or triple bond

In this step, we have to check whether the central atom (i.e carbon) has an octet or not.

In simple words, we have to check whether the central Carbon (C) atom is having 8 electrons or not.

As you can see from the above image, the central atom (i.e carbon) has only 4 electrons. So it does not fulfill the octet rule.

Now, in order to fulfill the octet of carbon atom, we have to move the electron pair from the outer atom (i.e selenium atom) to form a double bond.

Still, the octet of carbon atom is not fulfilled as it has only 6 electrons.

So again moving the electron pair from another selenium atom, we will get the following structure.

Now you can see from the above image that the central atom (i.e carbon), is having 8 electrons. So it fulfills the octet rule and the carbon atom is stable.

### Step #6: Final step – Check the stability of lewis structure by calculating the formal charge on each atom

Now, you have come to the final step and here you have to check the formal charge on carbon atom (C) as well as each selenium atom (Se).

For that, you need to remember the formula of formal charge;

Formal charge = Valence electrons – Nonbonding electrons – (Bonding electrons)/2

• For Carbon:
Valence electrons = 4 (as it is in group 14)
Nonbonding electrons = 0
Bonding electrons = 8
• For Selenium:
Valence electron = 6 (as it is in group 16)
Nonbonding electrons = 4
Bonding electrons = 4

So you can see above that the formal charges on carbon as well as selenium are “zero”.

Hence, there will not be any change in the above structure and the above lewis structure of CSe2 is the final stable structure only.

Each electron pair (:) in the lewis dot structure of CSe2 represents the single bond ( | ). So the above lewis dot structure of CSe2 can also be represented as shown below.

Related lewis structures for your practice:
Lewis Structure of BrCl
Lewis Structure of AsCl3
Lewis Structure of C2H2Br2
Lewis Structure of SbCl5
Lewis Structure of CH3SH